From the cross AABbCCddEe X aaBbCcDDee what portion of the p

.From the cross, AABbCCddEe X aaBbCcDDee, what portion of the progeny will be:

a. AabbCCDdee?

b. AaBBccDdEe?

c. AaB_C_DdEe?

d. AaBbCcDdEe?

e. AaBbCc and A_D_E_?

f. AaBbCc or A_D_E_?

g. AabbCcDdee or AaBBCCDdEe?

h. AabbCCDdee or AaB_C_DdEe or AaBbCcDdEe?

Solution

AA* aa -à Aa (100%)

Bb*Bb ----> BB, Bb, Bb, bb (means, 1/4th BB, 1/4th bb, 1/2 Bb)

CC*Cc ----> Cc, CC (1/2 CC and ½ Cc)

DD*dd ----à Dd (100% Dd)

Ee* ee -----à Ee, Ee (means, 1/2th ee, 1/2 Ee)

A). Thus, the probability of AabbCCDdee is, 1*1/4*1/2*1*1/2 = 1/16

B). Thus, the probability of AaBBccDdEe is, 1*1/4*0*1*1/2 = 0

C). Thus, the probability of AaB_C_DdEe is, 1*3/4*1*1*1/2 = 3/8

D). Thus, the probability of AaBbCcDdEe is, 1*1/2*1/2*1*1/2 = 1/8