Write an assembly program which stores 0 times 30 in all mem

Write an assembly program which stores 0 times 30 in all memory locations between memory addresses AO and A1, including AO and A1. A1 is greater than AO. Assume A1 is 0x0000.2020 and A0 is 0x0000.2000. Simulate the program in ARMSim to verify its correctness and do the following: List the complete program in this answer sheet. Make sure you comment each instruction properly. Attach the screenshot of your final simulation result. You can open a MemoryView window by pressing View Memory in ARMSim. You can then type in the address of A0 and view the content of memory locations start from A0.

Solution

In ARM memory address space every sequential address will be increased by 4 in hexadecimal form. So we will store 0x32 number at locations showing in the below mentined program.

Mnemonic Operands        Comment
MOV r0, #0x32           ; r0 = 0x32
MOV            r1, #0x00002000       ; r1 = the target address
STR            r0, [r1]            ; *r1 = r0 means it store 0x32 at location given to adress given in r1 register
MOV            r1, #0x00002004       ; r1 = next sequential target address
STR            r0, [r1]
MOV            r1, #0x00002008       ; r1 = next sequential target address
STR            r0, [r1]
MOV            r1, #0x00002012       ; r1 = next sequential target address
STR            r0, [r1]
MOV            r1, #0x00002016       ; r1 = next sequential target address
STR            r0, [r1]
MOV            r1, #0x00002020       ; r1 = next sequential target address
STR            r0, [r1]