A subject whose weight is 700 N is measured in an ADP chambe

A subject whose weight is 700 N is measured in an ADP chamber. The volume of the chamber is 0.4500 m33. A measurement of the chamber volume with the subject is 0.3839 m3m3. Next, the volume of the lungs is recorded as 0.0042 m33. All of these values are determined assuming an adiabatic environment. In order to correct for the isothermal environment in the lungs, what is the value that must be added on to the raw measurement of body volume?


A simple answer of 0.0042 is incorrect.

Solution

Solution :

So we know the volume of chamber-= 0.4500 m³

Because of the volume of the lungs the extra measurement of 0.0042 m³ will exist and remember this cant be ignored and rectified because its natural.

So instead of trying to nullify the effect we add the lung volume to the actual volume 0.4500+0.0042= 0.4542 m³

This is done so that we are not prone to errors.