In a normal distribution of acheivement test scores with a m

In a normal distribution of acheivement test scores, with a mean of 600 and a standard deviation of 60, find the T score:

for a raw score of 400

for a raw score of 710

Solution

As

t = (x - X)/s, then

a)

Here, X = 600, s = 60.

Hence, for x = 400,

t = (400-600)/60 = -3.3333 [answer]

*************

b)

For x = 710,

t = (710 - 600)/60 = 1.83333 [answer]