assume if you need SLIDER VELOCITY just mention what you ass

assume if you need SLIDER VELOCITY

just mention what you assume

For the figures shown below, if omega_1 = 10 rad/s, solve for omega_2 Use vector methods Use complex number method

solution;

assume angle of crank=a1=30

loop closure equation is

R1\'+R2\'=R3\'+R4\'

R1=1.5,a1=30

R2=3,R3=d,a3=0

R4=.5,a4=90

hence by separating i and j term we get for j termsas

1.5cos30+3sina2=.5

on solving we get

a2=-4.780

on differentiating loop closure equation we get

Vp=d\'d^=R1w1(r1^*K1^)+r2w2(R2^*K2^)

on solving for j term we get

15cos30+3w2cos(-4.78)=0

w2=-4.3452 rad/s

3) here by complex algebra method loop closure equation is written as

R1e^(i30)+v+R2e^(ia2)-de^(i0)-R4e^(i90)=0

on solving for imaginary part we get

1.5sin30+3sina2=.5

on solving we get

a2=-4.78

on differentiatig loop closure equation we get

Vp=-(R1w1sin30+R2w2sin(-4.78))+i(R1w1cos30+R2w2cos4.78)

for imaginary partwe get

R1w1cos30=-R2w2cos4.78

w2=-4.34520rad/s