Of the coffee makers sold in an appliance store 6 have eithe

Of the coffee makers sold in an appliance store, 6% have either a faulty switch or a defective cord, 2.6% have a faulty switch, and 0.1% have both defects. What is the probability that a coffee maker will have a defective cord given that it has either a faulty switch or defective cord? Give results to the nearest thousandth.

Solution

Let

S = faulty switch
C = faulty cord

As

P(C U S) = P(C) + P(S) - P(C n S)

0.06 = P(C) + 0.026 - 0.001

Thus,

P(C) = 0.035

Thus,

P(C|C U S) = P(C)/P(C U S) = 0.035/0.06 = 0.583 [ANSWER]