Water and Carbohydrates Continuing on the theme of fruits an
Solution
1. Ho : rho=0 VS H1: rho does not equal to 0
The calculated rho value is -0.9926842.
2. Critical value of t-distribution for 5% level of significance with 6 degree of freedom is 2.4469.
3. Computation of test statistic
t={rho(sqrt(n-2))}/{sqrt(1-rho^2}={-.9927*sqrt(7-2)}/{sqrt(1-(-0.9927)^2)}= --18.3843
4. Reject the null hypothesis and Accept the alternative hypothesis.
5. Conclusion. Since calculated | t | is greater than critical t value (2.4469), H1 accepted strongly at 5% level of significance and we may conclude that the water and carbonhydrate contain in the theme of fruits and vegitable is significantly negative correlation.
6 The linera regression model is
y= 87.408+(- 0.868)x
8. y=87.408+(- 0.868)*75
y=22.31
The carbohydrate value at 75gm of water is 22.31 gm.
