Can someone please help break this question down by steps Th

Can someone please help break this question down by steps? Thank you

Huggers Polls contend that an agent conducts a mean of 53 in-depth home survey’s every week. A streamlined survey form has been introduced, and Hugger want to evaluate its effectives. The number of in-depth surveys conducted during a week by a random sample of agents are:

53

57

50

55

58

54

60

52

59

62

60

60

51

59

56

At the .05 significance level can we conclude that the mean number of interviews conducted by their agents is more than 53 per week?

Solution

Set Up Hypothesis
Null, H0: U=53
Alternate, H1: U>53
Test Statistic
Population Mean(U)=53
Sample X(Mean)=56.375
Standard Deviation(S.D)=3.6124
Number (n)=16
we use Test Statistic (t) = x-U/(s.d/Sqrt(n))
to =56.375-53/(3.6124/Sqrt(15))
to =3.737
| to | =3.737
Critical Value
The Value of |t | with n-1 = 15 d.f is 1.753
We got |to| =3.737 & | t | =1.753
Make Decision
Hence Value of | to | > | t | and Here we Reject Ho
P-Value :Right Tail - Ha : ( P > 3.7371 ) = 0.00099
Hence Value of P0.05 > 0.00099,Here we Reject Ho

we conclude that the mean number of interviews conducted by their agents is more than 53

Can someone please help break this question down by steps? Thank you Huggers Polls contend that an agent conducts a mean of 53 in-depth home survey’s every week

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