Homework Soursen1430 p45SolutionHere mean u n p 143045 1144 answer stand
n=1430, p=4/5
Solution
Here,
mean (u) = n p = 1430*(4/5) = 1144 [answer]
standard deviation (sigma) = sqrt(n p(1 - p)) = sqrt(1430*(4/5)*(1-4/5)) = 15.12613632 [answer]
Thus, the usual values area between
lower bound = u - 2*sigma = 1113.747727
upper bound = u + 2*sigma = 1174.252273
The usual values are between 1113.7477 and 1174.2523 [answer]
![n=1430, p=4/5SolutionHere, mean (u) = n p = 1430*(4/5) = 1144 [answer] standard deviation (sigma) = sqrt(n p(1 - p)) = sqrt(1430*(4/5)*(1-4/5)) = 15.12613632 [a](/WebImages/7/n1430-p45solutionhere-mean-u-n-p-143045-1144-answer-stand-990170-1761509065-0.webp "n=1430, p=4/5SolutionHere, mean (u) = n p = 1430*(4/5) = 1144 [answer] standard deviation (sigma) = sqrt(n p(1 - p)) = sqrt(1430*(4/5)*(1-4/5)) = 15.12613632 [a")
