THERMODYNAMICS HOMEWORK DUE TOMORROW PLEASE HELP ASAP Propan

THERMODYNAMICS HOMEWORK DUE TOMORROW PLEASE HELP ASAP.

Propane at 70 C and 101.3 kPa is compressed isothermally to 1500 kpa. Calculate the change in enthalpy for the process by a suitable generalized correlation.

Solution

Basically enthalpy is

chnage in enthalpy is equal to sum of change in iternal energy and change in PV

dH = dE + d(PV)

for isothermal process dE=0 ( as there is no change in temperature.)

As they havent mentioned anything take propane as ideal gas

for ideal PV= mRT

as T is constant PV = constant

Therfore d(PV) = 0

so dH = 0+0 = 0