evaluate the improper integral from x0 to x1 1sqrtxdxSolutio
evaluate the improper integral. from x=0 to x=1  1/(sqrt(x))dx
Solution
1/x = 1/x1/2 and can be rewrited as x-1/2
the integral = x(-1/2 +1)/(1/2 + 1) = x1/2 /(1/2) = 2x1/2/1 = 2x1/2 from 0 to 1
=2(1)1/2 - 2(0)1/2 = 2 -0 =2

