evaluate the improper integral from x0 to x1 1sqrtxdxSolutio

evaluate the improper integral. from x=0 to x=1 1/(sqrt(x))dx

Solution

1/x = 1/x1/2 and can be rewrited as x-1/2

the integral = x(-1/2 +1)/(1/2 + 1) = x1/2 /(1/2) = 2x1/2/1 = 2x1/2 from 0 to 1

=2(1)1/2 - 2(0)1/2 = 2 -0 =2

evaluate the improper integral. from x=0 to x=1 1/(sqrt(x))dxSolution1/x = 1/x1/2 and can be rewrited as x-1/2 the integral = x(-1/2 +1)/(1/2 + 1) = x1/2 /(1/2)

Get Help Now

Submit a Take Down Notice

Tutor
Tutor: Dr Jack
Most rated tutor on our site