Seedless green grapes are sold in mess bags at Winn Dixie an

Seedless green grapes are sold in mess bags at Winn Dixie and typically consist of 3-5 bunches per bag. Suppose the weight of these bags follows a normal distribution with a mean and standard deviation based on the table to the right. Determine the probability that a randomly selected bag will contain the value indicated below?

The randomly selected bag will contain 35.0 ounces (Bag weight in ounces µ = 27.2 = 4.8)

Solution

Normal Distribution
Mean ( u ) =27.2
Standard Deviation ( sd )=4.8
Normal Distribution = Z= X- u / sd ~ N(0,1)                  
a)
P(X > 35) = (35-27.2)/4.8
= 7.8/4.8 = 1.625
= P ( Z >1.625) From Standard Normal Table
= 0.0521                  

P(X < = 35) = (1 - P(X > 35)
= 1 - 0.0521 = 0.9479