Have you ever noticed when watching a National Football Leag
Have you ever noticed, when watching a National Football League (NFL) game, that the players spend a lot of time standing around between plays? The following data were collected from a random sample of 12 NFL games. (See exercise 49 on page 373 of your textbook for a similar problem.)
Minutes standing around between plays
64.73
60.49
69.34
71.22
65.59
71.42
57.16
55.64
71.40
73.62
62.80
67.76
Question 3 A Test the hypothesis that the average time NFL players spend standing around between plays during a game is 59.69 minutes at =0.1.
Step 1:
H0: µ
Ha: µ >
Step 2: =
Step 3: Fill in the row if the hypothesis is one tailed.
Reject H0 if
Fill in the row if the hypothesis is two tailed. The smaller number must be typed first.
Reject H0 if or
Step 4: =
Step 5: H0
Step 6:
Step 7: Fill in the row if the Z table is appropriate.
P-value =
Fill in the row if the t table is appropriate. The lower boundary must go on the left and the upper boundary on the right.
P-value
Question 3 B Construct a 99% confidence interval for the population average time NFL players spend standing around between plays during a game.
Lower Endpoint Upper Endpoint
Question 3 C What would the P-value be if this were a lower tail hypothesis test? (Mathematically manipulate the P-value from part A to get your answer.)
Fill in the row if the Z table is appropriate.
P-value =
Fill in the row if the t table is appropriate. The lower boundary must go on the left and the upper boundary on the right.
(Lower Boundary) P-value (Upper Boundary)
Solution
Given that, when watching a National Football League (NFL) game, that the players spend a lot of time standing around between plays.The following data were collected from a random sample of 12 NFL games.
n = number of NFL games = 12
We want to test the hypothesis that ,average time NFL players spend standing around between plays during a game is 59.69 minutes.
It can be written as symbolically,
H0 : µ = 59.69 minutes Vs H1 : µ 59.69 minutes.
Since it is an two sided test.
Sample data is given and population standard deviation is unknown so we use t-statistic here.
t = (xbar - µ) / [s / sqrt(n)]
This t-distribution follows with n-1 degrees of freedom.
xbar = x / n = average of the observations.
s = (x - xbar)^2 / (n-1) = standard deviation of observations.
We can make the table for calculating t-statistics is,
By using EXCEL we can compute the values as,
t-statistic = 3.64999
Given that = 0.1
P-value can be calculated by using the command in EXCEL as :
=tdist(x,degrees of freedom,tails)
=tdist(3.64999,11,2)
P-value = 0.003821
By using P-value we can take a decision that is,
If P-value < then reject H0 at % level of significance.
and if P-value > then fail to reject H0 at % level of significance.
So here P-value < reject H0 at % level of significance.
Conclusion : average time NFL players spend standing around between plays during a game is differ from 59.69 minutes.
Construct a 99% confidence interval for the population average time NFL players spend standing around between plays during a game.
c = confidence level = 0.99
xbar = 65.93083
s = 5.923001
n = 12
99% confidence interval for mean is ,
xbar - E < µ < xbar + E
Where E = tc * s/sqrt(n)
tc is the t-critical value = 3.4966
E = 3.4966 * 5.923001 / sqrt(12)
E = 5.9786
Lower limit = xbar - E = 59.9522
Upper limit = xbar + E = 71.9094
The 99% confidence interval for the population average time NFL players spend standing around between plays during a game is (59.9522 , 71.9094).
| x | (x-xbar)^2 | 
| 64.73 | 1.4420007 | 
| 60.49 | 29.602667 | 
| 69.34 | 11.622417 | 
| 71.22 | 27.975284 | 
| 65.59 | 0.1161674 | 
| 71.42 | 30.130951 | 
| 57.16 | 76.927517 | 
| 55.64 | 105.90125 | 
| 71.4 | 29.911784 | 
| 73.62 | 59.123284 | 
| 62.8 | 9.8021174 | 
| 67.76 | 3.3458507 | 
| 791.17 | 385.90129 | 



