The parallel plates of a photoelectric effect experiment are

The parallel plates of a photoelectric effect experiment are made of magnesium and separated by a distance of 0.15 m. The potential difference between the plates Is set to 6 0 V. Assuming the electric field between the plates is uniform and constant, what is the magnitude of the electric field?

Solution

Electric field between the parallel plates is

E = V / d

     = 6 V / 0.15 m

     = 40 V /m