Solve the triangle 27 105 Solutionc24262246 cos 105 c2 1636

Solution

c²=4²+6²-2(4)(6) cos 105

c²= 16+36- 48 cos 105

c²= 52 - 48 cos 105

c= 8.03

Sin 105/8.03= sin beta/6

sin beta= 6 sin 105/8.03

beta= 46.20 degree

Alpha=180- 105-46.2= 28.8 degree