For each locus in each population calculate the Heterozygosi

For each locus in each population calculate the Heterozygosity. Calculate the average heterozygosity for each population. Calculate the average population for both populations combined.

Solution

For population 1:

The frequency of genotype at each locus is:

Locus 1: Genotype BB = 2/5, DD = 1/5, BD = 1/5

Locus 2: Genotype AA = 2/5, AC = 1/5, AB = 2/5

Locus 3: Gentype AA = 1

Average heterozygosity = Heterozygosity of loci/total number of loci

= ( 0.2 + 0.6 + 0)/3

= 0.8/6 = 0.133

For Population 2:

Frequency at each loci:

Locus 1: BB = 2/5, BD = 1/5, BE = 1/5, DE = 1/5

Locus 2: BB = 1/5, AD = 1/5, AB = 1/5, AA = 1/5, AC = 1/5

Locus 3: AA = 1

Average heterozygosity for population 2 = ( 0.6 + 0.6 + 0)/3

= 0.4

Average Heterozygosity for both populations combined:

Locus 1: BB = 5/10, BD = 2/10, DD = 1/10, DE = 1/10, BE = 1/10

Locus 2: AA = 3/10, AC = 2/10, AB = 2/10, AD = 1/10, BB = 1/10, AC = 1/10

Locus 3: AA = 1

Average heterozygosity = (0.5 + 0.6 + 0)/3

= 1.1/3 = 0.37