Suppose that the average US household uses 11600 kWh kilowat

Suppose that the average U.S. household uses 11600 kWh (kilowatt-hours) of energy in a year. If the average rate of energy consumed by the house was instead diverted to lift a 1580 kg car 12.8 m into the air, how long would it take? Using the same rate of energy consumption, how long would it take to lift a loaded 747, with a mass of 395000 kg, to a cruising altitude of 9.67 km?

Solution

power = work / time = 1.16 * 10⁷ / (365 * 24)

= 1324 W

time = work / power = m g h / power

= (1580 * 9.8 * 12.8) / 1324 = 150 s