A volume of 00125 m3 at a temperature of 1300C and pressure

A volume of 0.0125 m³ at a temperature of 130⁰C and pressure at 90kPa has the temperature increased by 150^oF.

What is the new volume?

Solution

increase in temperature = 150 F = 65.556 C

As process is not mentioned, considering isobaric process (p=Constant)

New volume = V_f

= (T_f*V_i/T_i)

= 0.0125 * (1300+65.556)/1300

= 0.01313 m³