Find the solution of the exponential equation 13ex162 in ter

Find the solution of the exponential equation 13e^x-16=2 in terms of logarithms, or correct to four decimal places.

13e^(x-16) = 2

Taking natural log on both sided:

ln{13e^(x-16)} = ln2

ln13 + ln(e^(x-16) ) = ln2

(x-16) = ln2 -ln13

x- 16 = - 1.8718

x= 16 -1.8718

x = 14.1282 (solution)