Use the normal distribution of SAT critical reading scores f
Solution
A)
We first get the z score for the critical value. As z = (x - u) / s, then as
x = critical value = 675
u = mean = 509
s = standard deviation = 114
Thus,
z = (x - u) / s = 1.456140351
Thus, using a table/technology, the left tailed area of this is
P(z < 1.456140351 ) = 0.927323088 = 92.73% [answer]
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B)
We first get the z score for the critical value. As z = (x - u) / s, then as
x = critical value = 575
u = mean = 509
s = standard deviation = 114
Thus,
z = (x - u) / s = 0.578947368
Thus, using a table/technology, the right tailed area of this is
P(z > 0.578947368 ) = 0.281312343
So we expect 0.281312343*1000 = 281.312343 = 281 scores [ANSWER, 281]
