Find the velocity with which it hits the ground answer in un

Find the velocity with which it hits the ground. answer in units of m/s.

a robot probe drops a camera off the rim of a 532 m high cliff on Mars, where the free-fall acceleration is -3.7 m/s^2.

Solution

Thefree fallacceleration on mars cannot be negative like -3.7 m/sec^2. If the acceleration is negative then the camara dropped won\'t reach the ground of mass, on the other hand it flies away from mass with the negative acceleration.Moreover it is against the law of gravitation. So, the free fall acceleration should be 3.7m/s^2 and not -3.7m/s^2.

Taking the acceleration g, and height of drop H and the initial velocity u ,ground hitting velocity v , we write the equation of motion: v^2-u^2=2g*H. By data given, g=3.7m/s^2, u= 0 as it is is drop and H=532m, we get : v^2-0^2 = 2*9.8*.532. Therefore, v=sqrt(2*3.7*532)=62.74 m/s. So, the camar\'s velocity at the time it hits the ground =64.74m/s