A pipe with an outside diameter of 216 mm and a wall thickne
Solution
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Resove the 19kN force into two components vertical and horizontal.
Both produce bending moment about H, however the moment due to horizontal component will not produce any bending stress at H, as H is on the neutral axis.
The vertical component will produce a bending moment and torque about H
Fv = 19x1000xsin55 = 15564 N-m.
bending moment M = 15664 x 0.75 = 11673 N-m.
Bending stress = My / I = 50.2 n/mm2
The pressure inside the pipe produces longidudinal stress = pd/4t = 2.4x202 / 4x7 = 17.3 N/mm2
and circumferential stress = pd/2t = 2.4x202 / 2x7 = 34.6 N/mm2
Total stress in longitudinal direction = 50.2 + 17.3 = 67.5 N/mm2
Stress in circumferential direction = 34.6 N/mm2
Fv also produces a torque T =15564 x 1.25 = 19455 N-m
Shear stress due to torque = Tr / J = 167.4 N/mm2
At H two normal stresses 34.6 and 67.5 N/mm2 both perpendicular to each other and a shear stress 167.4 N/mm2
Max principal stress = 219.25 N/mm2
Min. principal stress = -117.15 N/mm2
Max shear stress = 168.2 n/mm2
