The second picture are the flies used in part one Can you al
The second picture are the flies used in part one.
Can you also use a punnet square too so that I can see how you arrived at the answer using that method?
I am just trying to learn how to do these type of problems.
Thank you so much!
Solution
Answer:
Wild wings = c+ ; curved wings= c
Wild eyes = se+ ; sepia eyes=se
c+c+ se+se+ X cc sese----------------Parents
c+ se+ c se---------------Gametes
c+c se+se (wild wings & wild eyes)----F1 (males and females are equal)
c+c se+se X c+c se+se
F2
Phenotypes= (both wild) : (wild wings & sepia eyes) : (curved wings & wild eyes) : (curved wings & wild eyes)
Phenotypic ratio: 9 : 3 : 3 : 1
In F2 ration also, all females and males are equal percentage as the genes are present on the autosomes.
| c+ se+ | c+ se | c se+ | c se | |
| c+ se+ | c+c+ se+se+ (both wild) | c+c+ se+se (both wild) | c+c se+se+ (both wild) | c+c se+se (both wild) |
| c+ se | c+c+ se+se(both wild) | c+c+ sese (wild wings & sepia eyes) | c+c se+se (both wild) | c+c sese (wild wings & sepia eyes) |
| c se+ | c+c se+se+ (both wild) | c+c se+se (both wild) | cc se+se+ (curved wings & wild eyes) | cc se+se (curved wings & wild eyes) |
| c se | c+c se+se (both wild) | c+c sese (wild wings & sepia eyes) | cc se+se (curved wings & wild eyes) | cc sese (curved wings &sepia eyes) |
