45 own more than one pet 60 own a dog Of those that has more

45% own more than one pet

60% own a dog

Of those that has more than one pet, 40% have a dog.

What are the chances that someone has a pet and is not a dog, and what are the chances that someone has more that one pet.

Solution

a)

Let A be a event which represents someone has a pet and is not a dog

P(A) = 1 - 0.6 = 0.4 = 40% ( since 60% own dog , the rest own pet other than dog)

b)

probability that someone has more than one pet but does not have dog

= 0.45 * (1-0.4)

= 0.27 = 27%

since 40% people owning more than one pet have dog , so the rest of the 60% people owning more than one pet have pets other than dog and 45% people own more than one pet