Suppose that the test scores in two classes were collected a
Solution
Formulating the null and alternative hypotheses,
Ho: u1 - u2 = 0
Ha: u1 - u2 =/ 0
At level of significance = 0.05
As we can see, this is a two tailed test.
Calculating the means of each group,
X1 = 78.9
X2 = 84.7
Calculating the standard deviations of each group,
s1 = 9
s2 = 7
Thus, the pooled standard deviation is given by
S = sqrt[((n1 - 1)s1^2 + (n2 - 1)(s2^2))/(n1 + n2 - 2)]
As n1 = 16 , n2 = 16
Then
S = 8.062257748
Thus, the standard error of the difference is
Sd = S sqrt (1/n1 + 1/n2) = 2.850438563
As ud = the hypothesized difference between means = 0 , then
t = [X1 - X2 - ud]/Sd = -2.034774605
Getting the critical value using table/technology,
df = n1 + n2 - 2 = 30
tcrit = +/- 2.042272456
Getting the p value using technology,
p = 0.050794301
As |t| < 2.0422, and P > 0.05, we FAIL TO REJECT THE NULL HYPOTHESIS.
Thus, there is no significant evidence that there is a difference between the two means of the classes. [CONCLUSION]
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Hi! If you use another method/formula in calculating the degrees of freedom in this two tailed test, please resubmit this question together with the formula/method you use in determining the degrees of freedom. That way we can continue helping you! Thanks!
