Suppose that the test scores in two classes were collected a

Suppose that the test scores in two classes were collected, and data was summarized as follows: Class I n=16 mean = 78.9 S = 9 Class II n=16 mean = 84.7 S = 7. Assuming the populations\' variances are equal, test, at the 0.05 level of significance, if there is a difference between the two means of the classes, by showing all the steps and information needed in the calculations.

Solution

Formulating the null and alternative hypotheses,              
              
Ho:   u1 - u2   =   0  
Ha:   u1 - u2   =/   0  
At level of significance =    0.05          
As we can see, this is a    two   tailed test.      
Calculating the means of each group,              
              
X1 =    78.9          
X2 =    84.7          
              
Calculating the standard deviations of each group,              
              
s1 =    9          
s2 =    7          
              
Thus, the pooled standard deviation is given by              
              
S = sqrt[((n1 - 1)s1^2 + (n2 - 1)(s2^2))/(n1 + n2 - 2)]               
              
As n1 =    16   , n2 =    16  
              
Then              
              
S =    8.062257748          
              
Thus, the standard error of the difference is              
              
Sd = S sqrt (1/n1 + 1/n2) =    2.850438563          
              
As ud = the hypothesized difference between means =    0   , then      
              
t = [X1 - X2 - ud]/Sd =    -2.034774605          
              
Getting the critical value using table/technology,              
df = n1 + n2 - 2 =    30          
tcrit =    +/-   2.042272456      
              
Getting the p value using technology,              
              
p =    0.050794301          
              
As |t| < 2.0422, and P > 0.05, we   FAIL TO REJECT THE NULL HYPOTHESIS.          

Thus, there is no significant evidence that there is a difference between the two means of the classes. [CONCLUSION]

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Hi! If you use another method/formula in calculating the degrees of freedom in this two tailed test, please resubmit this question together with the formula/method you use in determining the degrees of freedom. That way we can continue helping you! Thanks!

 Suppose that the test scores in two classes were collected, and data was summarized as follows: Class I n=16 mean = 78.9 S = 9 Class II n=16 mean = 84.7 S = 7.

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