From a boat on the lake the angle of elevation to the top of
From a boat on the lake, the angle of elevation to the top of a cliff is
17°37\'.
If the base of the cliff is
968
feet from the boat, how high is the cliff (to the nearest foot)?
Solution
tan = opp/adj
17°37 = 17 + 37/60 = 17.62°, radians = (17.62°/180°)pi = 0.308 radians
968 *tan(0.308 radians) = 307.44 ft
