Find the coefficient of variation and then compare the varia
Find the coefficient of variation and then compare the variation in the following sets of data.
| Jefferson Valley (single line): | 6.5 | 6.6 | 6.7 | 6.8 | 7.1 | 7.3 | 7.4 | 7.7 | 7.7 | 7.7 | |
| Providence (individual lines): | 4.2 | 5.4 | 5.8 | 6.2 | 6.7 | 7.7 | 7.7 | 8.5 | 9.3 | 10 |
Solution
Cv=sd/mean*100
Jefferson Valley
mean=7.15
sd=0.4766
cv=6.66%
Providence
mean=7.15
sd=1.8216
cv=25.47%
The Jefferson Valley data has lesser variation.
