Find the limit below lim t2 5t 3t 2 t 22t 3 Solutionlim t

Find the limit below.

lim t2

=

Solution

lim t --> 2 5 (t+3) (t-2)(t-2)(2t-3)

= lim t--->2 ( t + 3) = 5

lim t-->2 ( t-2) = 0

lim t-->2 ( t -2 ) = 0

lim t-->2 ( 2t - 3) = 1

therefore, we have

5*5*0*0*1 = 0

hence, final value is 0