You perform a cotransformation mapping experiment using two

You perform a cotransformation mapping experiment using two strains of E. coli.

The first strain has the genotype a- b- c-.

The second strain has the genotype a+ b+ c+.

The results of the experiment are shown in this data table.

Gene locations are ---c--a--------------------b--- (approximately)

Also provided: The transformation frequency of the c gene alone (transformants a-b-c+) is 2.3, and the transformation of the b gene alone (transformants a-b+c-) is 2.8. The cotransformation frequency of the c and a genes (transformants a+b-c+) is 2.1. The similarity of this cotransformation frequency to the transformation frequency of calone indicates that the c and a genes are close together on the bacterial chromosome.

Although the cotransformation frequency of the c and b genes (transformants a-b+c+) is not known, the cotransformation of the a and b genes (transformants a+b+c-) is 0.095, which indicates that the a and b genes are far apart on the bacterial chromosome. Thus, the order of the genes must be c-a-b, with c and a close together, and a and b farther apart.

Based on the gene map, which number is closest to the frequency of a-b+c+ transformants that you would expect from this experiment?

answer is NOT 2.8%; please solve this last question and show work! :)

Genotype	a+ b- c-	a- b+ c-	a- b- c+	a+ b+ c-	a- b+ c+	a+ b- c+
% Transformants	3.4	2.8	2.3	0.095	not tested	2.1

You perform a cotransformation mapping experiment using two strains of E. coli. The first strain has the genotype a- b- c-. The second strain has the genotype a+ b+ c+. The results of the experiment are shown in this data table. Genotype 0.095 not tested 2.1 3.4 2.8 2.3 Transformants Drag the genes to their correct locations on the gene map below.

Solution

Solution) As discussed in the question itself that the gene order is \"cab\" such that genes \"c\" and \"a\" are closely placed and the gene \"b\" is distant from these two genes.

As we know that the genes closely related will have higher chances of getting co-transformed and their cotransformation frequency will be similar to the transformation efficiencies of each single gene.

but, the cotransformation frequency of two genes placed at a large distance can be calculated by multiplying their individual transformation frequencies.

In such case, cotransformation frequency of genes \"a\" and \"b\" = (transformation frequency of gene a x transformation frequency of gene b) / 100 = (3.4 x 2.8) / 100 = 0.0952 (it is given in the table already)

similarly, cotransformation frequency of genes \"b\" and \"c\" = (transformation frequency of gene b x transformation frequency of gene c) / 100 = (2.8 x 2.3) / 100 = 0.0644

Therefore, the cotransformation frequency of gene b and c would be 0.064