Solve the triangle A 65 degree a 6 b 10 C 35 degree a 1

Solve the triangle. A = 65 degree, a = 6, b = 10 C = 35 degree, a = 18.7, c = 16.1 a = 7, c = 11, B = 123 degree

Solution

2.A=65,a=6, b=10

usin sine law

sinA/a=sinB/b

sin 65/6=sinB/10

10sin65/6=sinB

Here we are getting sin B=1.51,and sin theta lies in [-1,1]. So in this case there is no solution

 Solve the triangle. A = 65 degree, a = 6, b = 10 C = 35 degree, a = 18.7, c = 16.1 a = 7, c = 11, B = 123 degree Solution2.A=65,a=6, b=10 usin sine law sinA/a=

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