In a sample of n16 selected from an underlying normal popula
In a sample of n=16 selected from an underlying normal population with S=10.
What is the value of X^2 statistic if you are testing the null hypothesis Ho that =7.5.
What is your statistical decision if
a.) H1 7.5
b.) H1 > 7.5
Solution
NOTE: Here, the level of significance is not given, so we assume it is 0.05.
a)
Formulating the null and alternative hypotheses,
Ho: sigma = 7.5
Ha: sigma =/ 7.5
As we can see, this is a two tailed test.
Thus, getting the critical chi^2, as alpha = 0.05 ,
alpha/2 = 0.025
df = N - 1 = 15
chi^2 (crit) = 6.262137795 and 27.48839286
Getting the test statistic, as
s = sample standard deviation = 10
sigmao = hypothesized standard deviation = 7.5
n = sample size = 16
Thus, chi^2 = (N - 1)(s/sigmao)^2 = 26.66666667 [ANSWER, CHI^2 STATISTIC]
As chi^2 is between the two critical values, we FAIL TO REJECT THE NULL HYPOTHESIS. [
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b)
Formulating the null and alternative hypotheses,
Ho: sigma <= 7.5
Ha: sigma > 7.5
As we can see, this is a right tailed test.
Thus, getting the critical chi^2, as alpha = 0.05 ,
alpha = 0.05
df = N - 1 = 15
chi^2 (crit) = 24.99579014
Getting the test statistic, as
s = sample standard deviation = 10
sigmao = hypothesized standard deviation = 7.5
n = sample size = 16
Thus, chi^2 = (N - 1)(s/sigmao)^2 = 26.66666667
As chi^2 > chi^2(crit), then we REJECT THE NULL HYPOTHESIS.

