Problem 1 Design and detail a reinforced concrete beam with
Solution
Solution:-
Given
b =20 inch ,h = 24 inch
Let cover = 2 inch
Effective depth(d) =22 inch
fy =60000 psi , fck =4500 psi
(1) Mu = 0.87fyAst(d - fyAst/(fckb))
250 *12*103 = 0.87*60000*Ast(22 – 60000Ast/(4500*20))
Ast = 2.96 inch2
Let 1.28 inch diameter bars are used
Total number of bars = 2.96/(/4*(1.128)2)
= 3
(2)
When Mu = 550*12*103 lb-inch
550*12*103 = 0.87*60000*Ast*(22 – 60000Ast/(4500*20))
Ast = 7.848 inch2
Provide 1.128 inch diameter bars
Total number of bars = 7.848/(/4*(1.128)2)
= 8
(3) When Mu = 800 feet- k = 800 *12*103 lb-inch
Ast = Mu/(0.87fy(d -0.42xmax)
Xmax =0.48*d =0.48 *22 =10.56 inch
Ast = 800 *12*106/(0.87*60000(22 – 0.42*10.56))
Ast = 10.47 inch2
Let 1.128 inch diameter bars are used
Total number of bars = 10.47/(/4*(1.128)2)
= 11
