An average of 2 cars cross the Mackinac Bridge toll plaza ev
Solution
We have given that an average of two cars cross the Machinac bridge toll plaza every 5 minutes.
We have to find the probability that more than 3 cars cross the toll plaza between 1.00 pm to 1.30 pm.
For every 5 minutes on an average 2 cars cross the bridge then for every 10 minutes on an average 2*2 cars cross the bridge.
Let X be a random variable that number of cars cross the toll plaza.
X ~ poison(mean =4)
We have to find the probability that,
P(X > 3) = 1 - P(X3) = 1 - [ P(X=0) + P(X=1) + P(X=2) + P(X = 3) ]
The pmf pf Poison distribution is,
P(X = x) = e-4 4x / x!
Now we have to find Probabilities for x=0,1,2 and 3.
P(X=0) = e-4 40 / 0! = 0.0183
P(X=1) = e-4 41 / 1! = 0.0733
P(X=2) = e-4 42 / 2! = 0.1465
P(X=3) = e-4 43 / 3! = 0.1954
P(X > 3) = 1 - [ 0.0183 + 0.0733 + 0.1465 + 0.1954 ]
P(X > 3) = 0.5665
