thanks Consider the type of flash lights chargeable or not c

thanks

Consider the type of flash lights (chargeable or not chargeable) purchased by each of six different customers at a certain store. If the probability that at most two of these purchase a chargeable light is .536. what is the probability that at least three purchase a non- chargeable light? If P(all six purchase chargeable)= 0.214. what is the probability that at least one of each type is purchased? At a restaurant for a fixed price you may choose from one of five entrees (grilled chicken, grilled beef, penne pasta, cheese ravioli, salmon), one of four salads (chicken salad, house salad, spring mix salad, tuna salad), three desserts (tiramisu. carrot cake, chocolate mousse) and four appetizers (chicken wing, fries, fried calamari. garlic bread). Use the product rules to answer the following questions: How many different meals are possible, if you must select one salad, one entree, one dessert and one appetizer? How many different meals are possible, if both the entree and the appetizer should have chicken in it? How many different meals are possible, if none should have chicken? How many different meals are possible, if at least one of them (entree, dessert, salad, appetizer) should have chicken in it? A box in a certain supply room contains four green balls, six red balls, six yellow balls, and four blue balls. Suppose that four balls are randomly selected. What is the probability that exactly three of the selected balls are red? What is the probability7 that all four of the selected balls have the same color? What is the probability that one ball of each type is selected? Suppose now that balls are to be selected one by one until a red ball is found. What is the probability7 that it is necessary to examine at least eight balls?

Solution

5)

a)
number of different meals possible

= 5C1 * 4C1 * 3C1 * 4C1 = 240

b)

number of different meals possible

= 1 * 4C1 * 3C1 * 1 = 12

c)

number of different possibilities

= 4C1 * 3C1 * 3C1 * 3C1 = 108

d)

number of different possibilities

= total possibilites - no chicken possibilites

= 240 -108

= 132