Given a hydropowerplant with a 170 m drop in water level and

Given a hydro-powerplant with a 170 m drop in water level and a total discharge mass flowrate of 1, 200,000 kg/s. The steadyflow process is adiabatic. The maximum possible average power output from the plant is approximately =

Solution

Given

Drp in water level, H =170m

mass flow rate, m = 1,200,000 kg/s

Maximum possible average power output from the plant

P = mgH

= 1,200,000 x 9.81 x 170

= 2001240000 W

= 2001240000 X 10^-6

= 2001.24 MW..................(Answer)