4sin2x12cos2xSolution4sin2x 12cos2x I understand its a trig

4sin²(x)=12cos²(x)

Solution

4sin^2x = 12cos^2x

I understand its a trigonometric equation to be solved for x:

So, 4sin^2x - 12(1-sin^2x) =0

16sin^2x = 12

sin^2x = 3/4

sinx = +/-sqrt(3)/2

x= sin(-sqrt3/2) ----> x = 2k*pi + 7pi/6 , 2k*pi +11pi/6

x = sin(sqrt(3)/2) -----> x = 2k*pi +pi/3 , x = 2k*pi +2pi/3

General solution :x = 2k*pi + 7pi/6 , 2k*pi +11pi/6

                     x = 2k*pi +pi/3 , x = 2k*pi +2pi/3