Problem I The following genotype frequencies are observed in

Problem I. The following genotype frequencies are observed in a population. Show that the population is NOT at Hardy Weinberg Equilibrium (HWE). (Note that in problems I assign, populations will either conform exactly to HWE or be substantially different. No need to do a chi square test on it.) Frequency of AA = 0.2 Frequency of Aa = 0.2 Frequency of aa = 0.6 Name one possible explanation for the deviation from HWE.

Solution

In this following question we need to focus onto the deviations from Hardy-Weinberg equilibrium(HWE): Generally we have seen HWE predicts that allelic frequencies remain constant from one generation to another. But here we can see the complete deviation where the recessive allele is having the highest frequency and domiant allele and heterozygous one also having less frequency.

In this we clearly suggest the process has occured through mating in random. Here an indivisual is equally likely to mate with any potential mate in the poulation regardless of their phenotype or genotypes. The diploid individuals are the result of gamete mixing. We are no applying or taking into consideration where the gametes are from any heterozygous or homozygous individual. Here we can say that the \"p\" value is 0.2 and \"q\" value 0.8, where gametes have met 80% of recessive allele to 20% of domiant ones, or depicting as a*A.