A girl running at a constant speed of 14ms in a straight lin
A girl running at a constant speed of 1.4m/s in a straight line throw a ball directly upward at 4.7 m/s. How far will she travel before the ball drops back into her hand? Ignore air fiction.
Solution
First find out how long the ball will be in the air,
 t = seconds
 Gravitational constant: -4.9 m/sec^2
 Upward velocity: +4.7 m/s
 :
 -4.9t^2 + 4.7t = 0
 t(-4.9t + 4.7) = 0
 Solutions:
 t = 0
 and
 -4.9t = -4.7
 t = -4.7/-4.9
 t = +.959 seconds
 :
 Find out how far she runs in .959 sec at a rate of 1.4 m/s
 :
 .959 * 1.4 = 1.346 m
 :She travels 1.346 meters from the time the ball is thrown until it is caught

