Consider a random variable z that has a standardized normal

Consider a random variable, z, that has a standardized normal distribution. Determine (-2 z 3).

Solution

z1 = lower z score =    -2      
z2 = upper z score =     3      
          
Using table/technology, the left tailed areas between these z scores is          
          
P(z < z1) =    0.022750132      
P(z < z2) =    0.998650102      
          
Thus, the area between them, by subtracting these areas, is          
          
P(z1 < z < z2) =    0.97589997   [answer]