The shear flow in each wall segment there are two cells and
Solution
Let, the reference line from where the centroid is to be measured is tangent to the dome of the semi-ellipse.
Calculation of the centroid is given in the following table:
Section
Area (a) in inch2
Distance of individual section from the reference line (x) in inch
a*x
a*x2
Iself
Elliptical
1
1.67
1.67
2.79
Rectangular
1.48
5.72
8.47
48.42
Triangular
21.2
19.28
408.74
7880.43
23.68
418.88
7931.64
The centroid = ( a*x)/ ( a) = 418.88/23.68 = 17.69 inch
Polar moment of inertia = Sum of the Polar moment of inertis of the individual sections about the centroid
= Iself + a*x2
This will give the value of the torsion constant (J)
| Section | Area (a) in inch2 | Distance of individual section from the reference line (x) in inch | a*x | a*x2 | Iself |
| Elliptical | 1 | 1.67 | 1.67 | 2.79 | |
| Rectangular | 1.48 | 5.72 | 8.47 | 48.42 | |
| Triangular | 21.2 | 19.28 | 408.74 | 7880.43 | |
| | 23.68 | | 418.88 | 7931.64 | |

