Form SolutionLet CO be the base of triangle Thus since PCO t

Solution

Let CO be the base of triangle

Thus, since PCO triangle is right angled we have:

sinx = PC/PO........1

cosy = CO/PO........2

we know that in the right triangle, PC^2 + CP^2 = OP^2

From 1 and 2 we have:

So, (sinx*PO)^2+(cosy*PO)^2 = OP^2

sinx^2 + cosy^2 = 1

So, relation between them is : sum of squares of sinx and cosy is 1