If a motor of a vehicle is running at a speed of V 200x1500

If a motor of a vehicle is running at a speed of V = (-200x+1500)/(0.4x+1) in rpm, where x is the location. At what time will the motor achieve a constant speed of 500rpm. Plot a graph using matlab for x(location) vs time t in seconds

Solution

V= (-200x+1500)/(0.4x+1), using V=500 rpm

x= 2.5

dV=2*pi*f

f=frecuency

V=2*pi*(1/T) = (-200x+1500)/(0.4x+1)

2*pi/ ((-200x+1500)/(0.4x+1))) = T

T= 2*pi*(0.4x+1) / (-200x+1500) so this equation is T vs x

using again 2.5

T= 0.015266 seg this is the time where V=500 rpm

I don´t have mathlab in this computer, but I graph it in excel, so here it goes:

Hope that this can help you, the code of mathlab is like this:

x=0:0.01:3;

Y=2*pi/ ((-200x+1500)/(0.4x+1)) ;

grid on

hold on

plot(x,y,\"r-\") ;