I have a sample of 50 trees and this sample gives me a stand
I have a sample of 50 trees and this sample gives me a standard error of 15 cm for mean tree height. If I double the replication, by how much do I reduce the error in mean tree height? Hint: use the equation for the standard error to deduce the standard deviation
Question 1 options:
By about a third
By about 10%
By about 10 times
By about half
| By about a third | |
| By about 10% | |
| By about 10 times | |
| By about half | 
Solution
standard error =s/vn =15
--> s/sqrt(50) = 15
--> s= 15*sqrt(50) =106.066
So double the replication:
standard error =s/vn =106.066/sqrt(50*2) =10.6066
1-10.6066/15 =0.2928933
Answer: By about a third

