solve the triangle Solve the following triangle using either

solve the triangle

Solve the following triangle using either the Law of Sines or the Law of Cosines. B = 29 degree, C = 97 degree, b = 2

Solution

by law of sines

b/sinB =c/sinC

2/sin29^o=c/sin97^o

c=2(sin97^o/sin29^o)

c=4.1

A+B+C =180^o

A+29+97=180

A=180-(29+97)

A=54^o

by law of sines a/sinA=b/sinB

a/sin54^o=2/sin29^o

a=2(sin54^o/sin29^o)

a=3.34

a=3.34,b=2,c=4.1,A=54^o,B=29^o,C=97^o