An election was held with five candidates a b cD and E and 5

An election was held with five candidates (a, b, c,D, and E) and 55 voters. The winner of the election was determined using the Borda Count Method. Suppose that A got 320 points, D got 221 points, C got 80 points, D got 113 points, and the points totals for E were lost. Give a complete ranking of the candidates in this election anyway!

Solution

The Borda count is a single-winner election method, in which voters rank options or candidates in order of preference. The Borda count determines the winner of an election by giving each candidate, for each ballot, a number of points corresponding to the number of candidates ranked lower. Once all votes have been counted the option or candidate with the most points is the winner.

We are given that 55 voters have cast their votes. Therefore, the total points scored is (55*5) + (55*4) + (55*3) + (55*2) +(55*1) = 275 + 220 + 165 + 110 + 55 = 825. The points scored by the candidates a, B, C, and D aggregate to 734. Therefore, the candidate C has scored 825 – 734 = 91 points. The rankings of the candidates are furnished in the table below:

Ranking

Candidate

Formula

Points

1st

A

n

320

2nd

B

n-1

221

3rd

D

n-2

113

4^th

E

n-3

91

5th

C

n-4

80

Ranking	Candidate	Formula	Points
1st	A	n	320
2nd	B	n-1	221
3rd	D	n-2	113
4th	E	n-3	91
5th	C	n-4	80