A 4kW electric resistance heater in a room is turned on and

A 4-kW electric resistance heater in a room is turned on and kept for 50 min. the amount of energy transfer to the room by the heater is kJ is (9000 kJ) (15000 kJ) (6000 kJ) (12000 kJ)

Solution

Solution :

We know that

Power= Energy/ time

Power= 4 KW= 4000 W

Time = 50 min = 50*60 = 3000 s

Hence

Energy = Power*time

Energy transferred = 4000*3000 = 12000 KJ

Correct option is OPTION D