2 Asector of a circle has an area of 10 square feet Find the

2- Asector of a circle has an area of 10 square feet. Find the central angle wich forms the sector if the radius is 5 feet 3- The blade of a circular saw rotate at a rate of 4750 revolutions per minute. What is the linear velicity in miles per hour of a point on the tip of the outer edge of a 7 1/4 inch diameter blade?

Solution

2- Asector of a circle has an area of 10 square feet. Find the central angle wich forms the sector if the radius is 5 feet

area of sector A=( /360^o)r²

given A=10 , r=5

10=( /360^o)*5²

( /360^o)=(10/(25))

=360^o(10/(25))

=45.84^o

central angle 45.84^o forms the sector