The sequence of a coding strand is AATATTCGAAGG If the stran

The sequence of a coding strand is AATATTCGAAGG. If the strand that is opposite to the above-given coding strand (i.e., the template strand) was transcribed to produce mRNA and the mRNA was translated to produce a peptide, what would be the amino acid sequence of the resulting peptide? Assume that translation of the mRNA begins with the first codon (i.e., assume that a start codon is not required to begin translation). Also, assume that if a stop codon is encountered prior to reaching the end of the mRNA, translation stops and does not resume, in which case you should enter the sequence of amino acid(s) incorporated into the peptide prior to encountering the stop codon. Use the Genetic Code to help you, and enter your answer using the one-letter code of amino acids.

coding strand 5\'-AATATTCGAAGG-3\'   

template strand 3\'-TTATAAGCTTCC-5\'

mRNA 5\'-AAUAUUCGAAGG-3\'

tRNA 3\'-UUAUAAGCUUCC-5\'

You read 5\' to 3\' so.....----> CCU UCG AAU AUU

CCU= Proline (P) UCG= Serine (S) AAU=ASN (N) AUU= Isoleucine (I) .......... But somehow PSNI is INCORRECT please help??

Solution

Coding strand : 5\'- AATATTCGAAGG -3\'

template strand : 3\'-TTATAAGCTTCC -5\'

mRNA : 5\'-AAUAUUCGAAGG-3\'

protein will be :   5\'-AAU AUU CGA AGG-3\'

Asn - Ile - Arg - Arg

Explanation : To translate the protein from mRNA we have to simply read triplets from the 5\' end of the mRNA.