Can someone please break this down step by step Thank you Th

Can someone please break this down step by step? Thank you

The dean at a large university in California wonders if students at the university study less than the 1961 national average of 24 hours per week. She randomly selects 35 student and asks their average study time per week in hours. From their responses she calculates a sample mean of 16.37 hours and a sample standard deviation of 7.22 hours. At the 5% significance level what can you conclude?

Solution

Set Up Hypothesis
Null, H0: U=24
Alternate,students at the university study less than the national average of 24 H1: U<24
Test Statistic
Population Mean(U)=24
Sample X(Mean)=16.37
Standard Deviation(S.D)=7.22
Number (n)=35
we use Test Statistic (t) = x-U/(s.d/Sqrt(n))
to =16.37-24/(7.22/Sqrt(34))
to =-6.252
| to | =6.252
Critical Value
The Value of |t | with n-1 = 34 d.f is 1.691
We got |to| =6.252 & | t | =1.691
Make Decision
Hence Value of | to | > | t | and Here we Reject Ho
P-Value :Left Tail -Ha : ( P < -6.252 ) = 0
Hence Value of P0.05 > 0,Here we Reject Ho

We have enough evidence to indicate that students at the university study less than
the 1961 national average of 24 hours per week

Can someone please break this down step by step? Thank you The dean at a large university in California wonders if students at the university study less than th

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