If the Vin is 1V what will be the additional power drawn fr

If the V_in is + 1V, what will be the additional power drawn from +V_cc and -V_ee? (where R_2 = 20k Ohm, R_1 = 10k Ohm, R_1 = 2k Ohm, +Vcc = 20V, -V_EE = -20V) 20mW from +V_cc OmW from -V_EE OmW from +V_cc, 20mW from -V_EE 20mW from +V_CC 20mW from -V_ee 30mW from +V+cc, OmW from -V_EE OmW from +V_cc, 30mW from -V_EE OmW from +V_CC OmW from -V_EE

Solution

2 Ans) (b)

It is in inverting amplifier Vo=-(R2/R1)*Vin=-2 V

Power to Resistor Rl is supplied by Vo as it is negative (-2 V) it is supplied by -V_EE

Load current IL=Vo/RL=-2/2k=-1 mA

This load current is to be supplied from -V_EE

So power supplied by -V_EE=-20*IL=-20*-1m=20 mW

So Ans is b) 0 Watts from Vcc and 20 mW from -V_EE